x^2-12x+33=0

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Solution for x^2-12x+33=0 equation:


Simplifying
x2 + -12x + 33 = 0

Reorder the terms:
33 + -12x + x2 = 0

Solving
33 + -12x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-33' to each side of the equation.
33 + -12x + -33 + x2 = 0 + -33

Reorder the terms:
33 + -33 + -12x + x2 = 0 + -33

Combine like terms: 33 + -33 = 0
0 + -12x + x2 = 0 + -33
-12x + x2 = 0 + -33

Combine like terms: 0 + -33 = -33
-12x + x2 = -33

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -33 + 36

Reorder the terms:
36 + -12x + x2 = -33 + 36

Combine like terms: -33 + 36 = 3
36 + -12x + x2 = 3

Factor a perfect square on the left side:
(x + -6)(x + -6) = 3

Calculate the square root of the right side: 1.732050808

Break this problem into two subproblems by setting 
(x + -6) equal to 1.732050808 and -1.732050808.

Subproblem 1

x + -6 = 1.732050808 Simplifying x + -6 = 1.732050808 Reorder the terms: -6 + x = 1.732050808 Solving -6 + x = 1.732050808 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + x = 1.732050808 + 6 Combine like terms: -6 + 6 = 0 0 + x = 1.732050808 + 6 x = 1.732050808 + 6 Combine like terms: 1.732050808 + 6 = 7.732050808 x = 7.732050808 Simplifying x = 7.732050808

Subproblem 2

x + -6 = -1.732050808 Simplifying x + -6 = -1.732050808 Reorder the terms: -6 + x = -1.732050808 Solving -6 + x = -1.732050808 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + x = -1.732050808 + 6 Combine like terms: -6 + 6 = 0 0 + x = -1.732050808 + 6 x = -1.732050808 + 6 Combine like terms: -1.732050808 + 6 = 4.267949192 x = 4.267949192 Simplifying x = 4.267949192

Solution

The solution to the problem is based on the solutions from the subproblems. x = {7.732050808, 4.267949192}

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